10x^2-56x+73=0

Solution for 10x^2-56x+73=0 equation:

10x^2-56x+73=0

a = 10; b = -56; c = +73;
Δ = b2-4ac
Δ = -562-4·10·73
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-6\sqrt{6}}{2*10}=\frac{56-6\sqrt{6}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+6\sqrt{6}}{2*10}=\frac{56+6\sqrt{6}}{20}
$